Question

The centre of circle 3x2+3y2-12x+15y-23=0 is

Answer 1

Answer:

2 , -5/2

Step-by-step explanation:

first you need to divide the equation by 3 to bring it in the standard form.

the centre of circle is given as

(-g , -f)

where, g and f are coefficients of x and y divided by 2

for extra information, standard form of equation of circle is

$x^{2} +y^{2}$+2gx+2fy+c= 0