Question

The centre of circle is 2a, - 7 find the value of a circle passes through the point 11, - 9 in has diameter 3 root 2 units

Answer 1

I think the diameter is not only.√2

here the diameter is 10√2

then radius =5√2

√(2a-11)²+(a-7+9)²=5√2

(2a-11)²+(a+2)²=(5√2)²

4a²-44a+121+a²+4a+4=50

5a²-40a+75=0

a²-8a+15=0

(a-3)(a-5)=0

a=3,5

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