Question

the centre of circle is (2k-1,3k+1) and it passes through point (-3,-1). find the value of k, if diameter of circle is of length 20 units​

Answer 1

Answer:

2 or -46/13

Step-by-step explanation:

distance between centre and point on circle is radius

by distance formula

√(2k-1-(-3))^2+ (3k+1-(-1))^2 = (20/2)

squaring

(2k+2)^2 + (3k+2)^2 = 100

4k^2+4+8k+9k^2+4+12k = 100

13k^2+20k+8 = 100

13k^2+20k-92=0

13k^2 -26k+46k-92=0

13k(k-2)+46(k-2) = 0

(13k+46)(k-2) = 0

k= -46/13 or 2

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