Question

The centre of circle passing through the points (5,7),(6,6) and (2,-2)

Answer 1

Answer:

x² + y² -18x -20y + 156 = 0

Step-by-step explanation:

equation of the line passing  (5,7),(6,6) is y-5/x-7 = 1/-1 , y-5= -x+7 , x+y -12 = 0

(x-x1)(x-x2) + (y-y1)(y-y2) - λ( x+y -12) = 0

(x-5)(x-6) + (y-7)(y-6) - λ( x+y -12) = 0

substituting the third point (2,-2) to get λ :

(2-5)(2-6) + (-2-7)(-2-6) - λ( 2-2 -12) = 0 , 12 + 72 -12 λ = 0 , λ = 7

(x-5)(x-6) + (y-7)(y-6) - 7( x+y -12) = 0

x² + y² -11x -13y -7x -7y +84 + 72 = 0

x² + y² -18x -20y + 156 = 0