Math, asked by nvramanasantha, 6 months ago

the centre of the circle x^2+y^2-2x+6y-6=0

Answers

Answered by pawanbhavanam2
0

Answer:

Step-by-step explanation:

Centre of given circle =(-g,-f)

Comparing with x^2+y^2+2gx+2fy+c=0

2g=-2

g=-1

-g=1

and 2f=6

f=3

-f=-3

Centre=(1,-3)

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