Question

the centroid of a triangle pqr where p(2,4) q(1,3)& r(x,y) is g(2,2).find the coordinates of r.

Answer 1

Answer:

Step-by-step explanation:

The coordinate of centroid of a triangle is x1+x2+x3/3,y1+y2+y3/3

Or2+1+x/3=2

x=3 also y=-1

Answer 2

Answer:

R (3,-1)

Step-by-step explanation:

The centroid of a triangle PQR is G(2,2)

The coordinate of ΔPQR,

P(2,4), Q(1,3) and R(x,y)

Formula for centroid:

$(x,y) = (\dfrac{x_1+x_2+x_3}{3},\dfrac{y_1+y_2+y_3}{3})$

$(2,2) = (\dfrac{2+1+x}{3},\dfrac{4+3+y}{3})$

$\dfrac{2+1+x}{3}=2$

$3+x=6$

$x=3$

$\dfrac{4+3+y}{3}=2$

$4+3+y=6$

$y=-1$

Hence, the coordinate of R (3,-1)