The centroid of the triangle whose vertices are A (1,-5), B (3,7) and C (5,10) is
a) G (3,-4)
b) G (0,9)
c) G (3, 4)
d) G (1,3)
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Answer:
Let the given vertices of a triangle be A(3,4) and B (−7,−2) let the third vertex be C (10,−5)
Let Centroid be G
centroid = [
3
x
1
+x
2
+x
3
,
3
y
1
+y
2
+y
3
]
G = [
3
3−7+10
,
3
4−2−5
]
G = (
3
6
,
3
−3
)
G = (2,−1)
x=2 , y=−1.
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