Question

The centroid of the triangle with vertices at (-2,-5),(-2,12) and (10,-1) is

Answer 1

$Let \: A (-2,-5) = (x_{1},y_{1}) , \\ B (-2,12) = (x_{2},y_{2}) , \\and \: C (10,-1) = (x_{3},y_{3})\: are \\ vertices \: of \: a \: triangle .$

$\boxed {\pink {Centroid (G) = \Big( \frac{x_{1}+x_{2}+x_{3}}{3} , \frac{y_{1}+y_{2}+y_{3}}{3} \Big)}}$

$= \Big( \frac{-2-2+10}{3}, \frac{-5+12-1}{3}\Big) \\=\Big( \frac{-4+10}{3} , \frac{-6+12}{3}\Big) \\= \Big(\frac{6}{3} , \frac{6}{3}\Big) \\= ( 2,2)$

Therefore.,

$\red{ Centroid \: of \: triangle } \green {= (2,2) }$

•••♪