Question

The change in the oxidation number of Pb and Cl in the reaction,
PbO, + TCO + Pb (OH), respectively are
(a) +2, + 2
(b) - 2, + 2
(c) + 2, - 1
(d) - 2, + 1​

Answer 1

Answer:

(d) - 2, + 1 is the correct answer

Answer 2

Corrected Question:

The change in the oxidation number of Pb and CI in the reaction

$PbO_2+Cl^- --- > ClO^-+Pb(OH)_3^-$, respectively are

(a) +2, + 2

(b) - 2, + 2

(c) + 2, - 1

(d) - 2, + 1​

​

Answer:

The correct answer is option (b) -2,+2.

Explanation:

Given reaction is,

$PbO_2+Cl^- --- > ClO^-+Pb(OH)_3^-$

From the above equation, we have

Oxidation number of Pb in $PbO_2$ = +4

Oxidation number of Pb in $Pb(OH)_3^-$ = +2

Change in oxidation number of Pb = +2 - (+4)  = 2-4 = -2

Oxidation number of Cl in $Cl^-$ = -1

Oxidation number of Cl in $ClO^-$ = +1

Change in oxidation number of Cl = +1 - (-1) = 1+1 = +2

Hence, the change in the oxidation numbers of Pb and Cl in the reaction are -2 and +2 respectively.

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