Question

the change in the surface energy when a drop of radius R spits into 8 droplets each of radius r is ??

Answer 1

Answer:Volume of the bigger drop = Total volume of 8 small droplets

(4/3) * Π * R³   =  8 x (4/3)* Π * r³

Now, r = R / 2  

Change in surface area = ds = 4* Π  * [8*r² - R²] = 4* Π * R²

Work done = T.ds = T* 4* Π * R²

Explanation:

Answer 2

Answer:

Volume of the bigger drop = Total volume of 8 small droplets

(4/3) * Π * R³ = 8 x (4/3)* Π * r³

Now, r = R / 2

Change in surface area = ds = 4* Π * [8*r² - R²] = 4* Π * R²

Work done = T.ds = T* 4* Π * R²

Explanation:

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