The charge on an electron is known to be 1.6 x 10-19 coulomb. In a circuit the current flowing is 1 A. How many electrons will be flowing through the circuit in a second?
Answers
Answered by
8
q = ne
t = 1 sec
I = 1 A
e = 1.6×10⁻¹⁹ C
and, current, I = q/t
⇒1 A = ne/1
⇒n×( 1.6×10⁻¹⁹) = 1
⇒n = 1/(1.6×10⁻¹⁹)
=6.25 ×10¹⁸ electrons
t = 1 sec
I = 1 A
e = 1.6×10⁻¹⁹ C
and, current, I = q/t
⇒1 A = ne/1
⇒n×( 1.6×10⁻¹⁹) = 1
⇒n = 1/(1.6×10⁻¹⁹)
=6.25 ×10¹⁸ electrons
Answered by
58
Answer:
Explanation:
Given :-
Current, I = 1 ampere
Charge, e = 1.6 × 10⁻¹⁹C
To Find :-
Number of electron, n =??
Formula to be used :-
I = ne
Solution :-
I = ne
n = I/e
n = 1/1.6 × 10⁻¹⁹C
n = 6.25 × 10⁻¹⁸ electrons.
Hence, Number of electron are 6.25 × 10⁻¹⁸ .
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