Chemistry, asked by kuldeeptripathi2307, 6 months ago

The charge present on 2.8 g of n3 in Columbus is

Answers

Answered by lalitnit
4

Answer:

Charge on one ion of N3−

=3×1.6×10^−19 coluomb

One g−ion=6.02×10^23 ions

Thus, charge on one g-ion of N3−

=3×1.6×10^−19×6.02×10^23

=2.89×10^5 coulomb.

Answered by rahul123437
1

The charge present on 2.8 g of N³⁻ion in Columbus is =2.89×10⁵ coloumb

Explanation:

Charge of one ion of N³⁻ion will be =3×1.6×10⁻¹⁹ coloumb

Charge on a single electron is 1.6 x 10⁻¹⁹ Coulomb

One gram ion will have ions =6.02 ×10²³ electron per mole

thus charge on one gram ion of N³⁻ion will be=3×1.6×10⁻¹⁹ ×6.02 ×10²³

=2.89×10⁵ coloumb

The charge present on  N³⁻ion in Columbus is calculated as 2.89×10⁵ coloumb.

Similar questions