The chord of a circle is equal to its radius. The angle subtended by this chord at the minor arc of the circle is
A) 60° B) 75° C) 120° D) 150°
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Solution
Consider the figure.
Given,
AB is equal to the radius of the circle.
In △OAB,
OA=OB=AB= radius of the circle.
Thus, △OAB is an equilateral triangle.
and ∠AOC=60°.
Also, ∠ACB=
2
1
∠AOB=
2
1
×60°=30°.
Since, ACBD is a cyclic quadrilateral,
∠ACB+∠ADB=180° ....[Opposite angles of cyclic quadrilateral are supplementary]
⇒∠ADB=180°−30°=150°.
Thus, angle subtend by the chord at a point on the minor arc and also at a point on the major arc are 150° and 30°, respectively.
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