Question

the chordsAB and CD of a circle intersect at O .If AO=5cm ,BO=3cm and CO=2.5cm then DO=?

Answer 1

Answer:

Step-by-step explanation:

When two chords intersect inside the circle,the product of their segments are equal.

AO*BO=CO*DO

DO=(AO*BO)/CO

DO=15/2.5

DO=6cm

Answer 2

here hi mate

QUESTION : the chordsAB and CD of a circle intersect at O .If AO=5cm ,BO=3cm and CO=2.5cm then DO=?

ANSWER : here AB AND CD intersect each other
that's why by property of chord
AO ×BO = CO×DO
5×3 = 2.5×CO

that's why co =6.

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