the circle has radius of 2 CM. an ant starts at A and walks around the circle in the order of ABCDA. it continues to walk in the circular direction for a distance of 167pi CM and it stop. where would the ant stop at?
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Step-by-step explanation:
It's clearly given that the ant moves around the circle in the order of A-B-C-D-A.
Now, the circumference of the circle is 2pi.r
So, C = 12.56 cm
The ant walks for a distance of 167 x Pi cm = 524.64 cm
Then, how many times is 12.56 cm equal to 524.64 cm? (that's, 524.64 ÷ 12.56 = 41.77 cm)
Also, how many times is 12.56 cm equal to 41.77 cm? (that's, 41.77 ÷ 12.56 = 37.68 cm)
Now, for a complete ABCDA, the ant will complete 12.56 cm of distance. Since, 12.56 x 3 = 37.68, the ant will stop at A because it makes three complete rotations around the circle.
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