The circular divisions of shown screw gauge are 50. It moves
0.5 mm on main scale in one rotation. The diameter of the
ball is
(a) 2.25 mm
(b) 2.20 mm
(c) 1.20 mm
(d) 1.25 mm
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12
Explanation:
Pitch of screw = 0.5mm
No. of division on circular Scale= 50
Least Count = Pitch/No. of division
= 0.5/50
= 0.01mm
Coinciding division = n * L.C
= 25 * 0.01
= 0.25mm
Diameter = 1.25mm
Answered by
22
Answer:Hope this helps.
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