Physics, asked by ShreyaDarban, 10 months ago

The circular divisions of shown screw gauge are 50. It moves
0.5 mm on main scale in one rotation. The diameter of the
ball is
(a) 2.25 mm
(b) 2.20 mm
(c) 1.20 mm
(d) 1.25 mm​

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Answers

Answered by manas3379
12

Explanation:

Pitch of screw = 0.5mm

No. of division on circular Scale= 50

Least Count = Pitch/No. of division

= 0.5/50

= 0.01mm

Coinciding division = n * L.C

= 25 * 0.01

= 0.25mm

Diameter = 1.25mm

Answered by vaishnavikatke30
22

Answer:Hope this helps.

Explanation:

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