Question

The circumferance of the second orbit of electron in hydrogen atom is 400 nm, the de broglie wavelength of electron corresponding

Answer 1

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Answer 2

Answer:

the de broglie wavelength of electron corresponding n=2

Explanation:

The wavelength (λ) this is related to an item in terms of its momentum and mass is referred to as de Broglie wavelength. A particle's de Broglie wavelength is normally inversely proportional to its force. λ = h m v = h momentum : where 'h' is the Plank's constant. This equation concerning the momentum of a particle with its wavelength is de Broglie equation and the wavelength calculated the usage of this relation is de Broglie wavelength.

According to wave-particle duality, the De Broglie wavelength is a wavelength manifested in all of the items in quantum mechanics which determines the opportunity density of locating the item at a given factor of the configuration space. The de Broglie wavelength of a particle is inversely proportional to its momentum.

Number of waves made via way of means of electron (n) =circumference / wavelength

n=400/200

n=2

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