the circumference of a base of a 12m high solid cone is 22m. find the volume. (take pie - 3.14)
Answers
Circumference of base = 22m
2πr=22
or,2×22/7×r=22
or,44r=22×7
or,r=22×7/44
or,r=7/2
Height=12m
Volume of cone =1/3×πrsquare h
=1/3×22/7×7/2×7/2×12
=77×2
=154m cu .
The volume of the cube is 153.2m^3.
Given
- circumference of a base of a 22m
- 12m high
- pie - 3.14
To find
- volume
solution
we are provided with the circumference of the base of a solid code and the height of the god as provided is 12 m and asked to find the volume of the cone.
For finding the volume of the cone, we need the height of the cone as well as the radius of the cone ,both of the values could be estimated from the given details and could be substituted in the standard equation to find the volume of the cone.
the circumference of the base is 22 m
2πr = 22
2(3.14)r = 22
or, 3.14r = 11
or, r = 3.5m
the height of the corners provided is 12 m
the volume of the cone is, 1/3 πr^2 h
V = 1/3 (3.14)(3.5)^2 × 12
or, V = 1/3 (3.14×12.2)×12
or, V = 1/3 (38.3×12)
or, V = 153.2 m^3
Therefore the volume of the cube is 153.2m^3.
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