the circumference of a circle is 132 cm find the side of a square inscribed in the circle
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Given data:-
• The circumference of a circle is 132 cm
Solution:-
Let, quadrilateral ABCD is a inscribed square.
{We need to find radius ( r ) of circle}
→ Perimeter of circle = 2πr
{From given}
→ 132 = 2 × 22/7 × r
→ 132 = 44/7 × r i.e.
→ r = {132 × 7}/44
→ r = 924/44
→ r = 175/44
→ r = 21 cm
According to figure AC is diameter.
AO & OC are radius of circle.
We know,
→ Diameter = 2 × radius
→ Diameter = 2 × 21
→ Diameter = 42 cm
::Properties of square::
- All side of square are equal in length.
- All angle of square are equal to 90° or they are called as right angle
- Diameter = 21 cm of circle is know to be hypotenuse of square according to fingure and Properties of square.
- According to property we can assime that → DC = BC = x
Now, we use pythagoras theorem to find side of square.
So, now from figure
→ (AD)² = (DC)² + (BC)²
→ (42)² = (x)² + (x)²
→ 1764 = 2x² i.e.
→ x² = 1764/2
→ x² = 882
→ x = √882 cm
→ x = 21√2 cm
Hence, the length of side of square is 21√2 cm.
{Note:- 21√2cm = 29.69848481 cm}
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