Question

The circumference of a circle is 22 cm. Find the area of its quadrant.,​

Answer 1

Answer:

these all based on basic proportionality theorem

have a nice day Yaar

but in the question u given area of quadrilateral ?

I can't understand that

Answer 2

Step-by-step explanation:

circumference =2 pi r

22= 2×(22/7)× r

r=7/2 cm

area of quadrant = pi r^2 /4

= (22/7) (7/2)^2 /4

= 22×7/16

= 154/16

= 9.625 cm^2

for question 24,

in triangle ABC, basic proportionality theorem

as LM parallel BC, so AM/MB = AL/ LC........(1)

similarly, in triangle ACD, as LN || CD

AN/ND = AL/ LC.....(2)

using eq1 and eq1

AM/MB = AN/ ND hence proved.