The circumference of a circle is 8 cm .find the area of sector whose central angle is 72° .
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Answered by
5
2 pie r = 8
r = 4/pie
area of sector = (pie r.r/360) × 72
= pie. 16/pie^2) ×5
= 16×5/pie
= 80 /pie = 25.47
r = 4/pie
area of sector = (pie r.r/360) × 72
= pie. 16/pie^2) ×5
= 16×5/pie
= 80 /pie = 25.47
Answered by
6
circumference=2πr
8cm=2πr
r=8/2π
r=4/πcm
theta=72°
area of sector=theta/360°×πr²
ar=72/360×π×4/π×4/π
ar=1/5×16/π=1/5×16×1/π
ar=1/5×16×7/22
ar=56/55cm²
area of sector=56/55cm²
8cm=2πr
r=8/2π
r=4/πcm
theta=72°
area of sector=theta/360°×πr²
ar=72/360×π×4/π×4/π
ar=1/5×16/π=1/5×16×1/π
ar=1/5×16×7/22
ar=56/55cm²
area of sector=56/55cm²
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