Question

the circumference of a steam roller is 2 metres and it is 6 decimeters wide. Ground passed over by the roller in 120 complete revolutions is ? Ans 144

Answer 1

plzz tell me details

Answer 2

Ground passed over by the roller in 120 complete revolutions is 143.88 m

Step-by-step explanation:

Circumference of roller = 2 m

Circumference = $2 \pi r$

So, $2 \pi r = 2$

$2 \times \frac{22}{7} r = 2$

$r = \frac{2 \times 7}{2 \times 22}$

$r=0.318 m$

1 dm = 0.1 m

Width of roller = 6 dm = 0.6 m

Curved surface area of roller = $2 \pi rh = 2 \times \frac{22}{7} \times 0.318 \times 0.6=1.199 m$

Area covered in 1220 revolutions = $1.199 \times 120 = 143.88 m$

Hence Ground passed over by the roller in 120 complete revolutions is 143.88 m

#Learn more:

A road roller takes 20 complete revolutions to move once over to level of a road find the area of a road if the radius of a road roller is 3.5 metre the height is 2 metre

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