Question

the circumference of circular faces of a frustrum are 132 cm and 88 cm and its height is 24 cm . to find the curved surface area of the frustrum complete the following activity π - 22/7​

Answer 1

Step-by-step explanation:

r1 = 132/2π

= 66/π

= (66 × 7)/22

= 3 × 7

= 21

r2 = 88/2π

= 44/π

= (44 × 7)/22

= 2 × 7

= 14

slant height

$l = \sqrt{ {h}^{2} + {(r1 - r2)}^{2} } \\ = \sqrt{ {24}^{2} + {(21 - 14)}^{2} } \\ = \sqrt{ {24}^{2} + {7}^{2} } \\ = \sqrt{576 + 49 } \\ = \sqrt{625} \\ = 25$

csa of frustum = πl(r1+r2)

$= \frac{22}{7} \times 25 \times (21 + 14) \\ = \frac{22}{7} \times 25 \times 35 \\ = 22 \times 25 \times 5 \\ = 22 \times 125 \\ = 2750$

hope you get your answer