the circumference of the base of 12m high wooden solid is 44m.find the volume of cone and total surface area
Answers
Answered by
58
circumference of circle=44
2πr=44⇒r=7m
Slant height of cone=√r²+h²⇒√193
Volume of cone=1/3πr²h⇒1/3x22/7x7x7x12=616m³
TSA of cone=πr(r+l)⇒22/7x7(7+√193)⇒22(7+13.89)⇒459.8m²
2πr=44⇒r=7m
Slant height of cone=√r²+h²⇒√193
Volume of cone=1/3πr²h⇒1/3x22/7x7x7x12=616m³
TSA of cone=πr(r+l)⇒22/7x7(7+√193)⇒22(7+13.89)⇒459.8m²
kaushikravikant:
your welcome
Answered by
34
Circumference of a circle= 44
2πr= 44
=7m
Salent height of circle= √r²+h²=√7²+12²=
√49+144= √193m
Volume of cone= 1/3πr²h= 1/3*22/7*7*7*12
=1296/21= 616m²
Total surface area of cone = πr(r+l)= 22/7*7(7=√193)
22(7+13.89)=616m²
2πr= 44
=7m
Salent height of circle= √r²+h²=√7²+12²=
√49+144= √193m
Volume of cone= 1/3πr²h= 1/3*22/7*7*7*12
=1296/21= 616m²
Total surface area of cone = πr(r+l)= 22/7*7(7=√193)
22(7+13.89)=616m²
Similar questions