The circumference of the base of a 9m
high wooden solid cone is 44 M find the volume of air contain in it
Answers
Answered by
46
:
The circumference of the base of a 9m high wooden solid cone is 44m. Find the volume of air contained in it.
:
h = 9 m
2πr = 44
2 × 3.14 × r = 44
r ~ 7cm
Volume of a cone = (πr^2h)/3
=(3.14×49×9)/3
=461.58 cubic meters (approx.)
The circumference of the base of a 9m high wooden solid cone is 44m. Find the volume of air contained in it.
:
h = 9 m
2πr = 44
2 × 3.14 × r = 44
r ~ 7cm
Volume of a cone = (πr^2h)/3
=(3.14×49×9)/3
=461.58 cubic meters (approx.)
Answered by
4
Answer:
Step-by-step explanation:
Given,
Circumference of the base of the cone is 44 m
hence,
2πr=44 m
2×22/7×r = 44 m
r = 44×7/44 m
hence, r=7 m(radius of base of cone.)
Now,
The volume of cone is given by
1/3πr^3
1/3×22/7×[7]^3
22×49/3
359.33 m ^3
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