Math, asked by arirt, 9 months ago

the cistern is filled in 12 hours when two pipes are made to function simultaneously . if one pipe fills the cistern 10 hours faster than the other , in how much time will the second pipe fill the cistern ?​

Answers

Answered by krishtiwari07
3

Answer:

Always try to solve these question by options to save time.

total time taken by both pipe

=(x)×(x+10)(x+10)+x

Now take out one option and put it in place of 'x'

x = 20 (from option (a))

(20)×(20+10)(20+10)+(20)=20×3050=12hrs

It matches with question figure. Total time matches. So, the answer is 20 hrs

Answered by evangelist89
0

Answer:

20 Hours second pipe fills cistern filled

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