Math, asked by nityagarg49, 5 months ago

The Class IX students of a certain public school wanted to give a farewell party to
the outgoing students of Class X. They decided to purchase two kinds of sweets, one
costing 370 per kg and the other costing 84 per kg. They estimated that 36 kg of
sweets were needed. If the total money spent on sweets was 2800, find how much sweets of each they purchased.​

Answers

Answered by kishornyk2
0

Answer:

77 is the answer

divide it u will get the answer

Answered by nityagarg25
12

Answer:

solution provided down

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Step-by-step explanation:

Let

The quantity of sweet costing Rs 70 be x and,

The quantity of sweet costing Rs 84 be y

Given, total quantity of sweets purchased is 34 kg

i.e., x+y=34 … (i)

Also given, the total money spent is Rs 2800

i.e., 70x+84y=2800 … (ii)

Multiplying (i) by 70, we get

70x+70y=2520 ... (iii)

Subtacting (ii) from (iii), we get

−14y=−280

⇒y=

−14

−280

⇒y=20

On substituting the value of y in equation (i), we get

x+20=36

⇒x=36–20

⇒x=16

Therefore, the quantities of sweets purchased are 16 kg which costs Rs 70 per kg and 20 kg which costs Rs 84 per kg.

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