Question

The class mark is 10 and its class widh is6.the lower limit of the class is

Answer 1

Answer:

since , class marks is 10 and class width is 6 .

then , let in the required class lower limit be x and the upper limit be y.

then , as we know that class width :--

= ( upper limit - lower limit).

= (y-x)

since, class width = 6

then , (y-x) = 6................. (i)

also, as we know that class marks = (upper limit + lower limit)/

====) (x+y)/2 = 10

====) x+y = 20................... (ii).

on adding equ.(i) & (ii). we have :--

2y=26

y = 13 ...

and therefore, x = 7.

hence the required class is 7-13

MARK THE BRAINLIEST....

PLZZZ