Question

The class marks of a distribution of the daily numbers of traffic accidents reported in a town are 8, 15, 22, 29 and 36. Determine class boundaries and class limits

Answer 1

⚡Here is your answer⚡

Hey here only frequency is given

where is the class mark.

✌Mahir✌

Answer 2

5.2

X P(X) X.P(x) [X - m] [X - m]2 P(X)*[X - m]2

0 0.1 0.00 -2.00 4.00 0.40

1 0.2 0.20 -1.00 1.00 0.20

2 0.45 0.90 0.00 0.00 0.00

3 0.15 0.45 1.00 1.00 0.15

4 0.05 0.20 2.00 4.00 0.20

5 0.05 0.25 3.00 9.00 0.45

m = 2.00 1.40

Mean = 2.0

Standard deviation = 1.18

5.1 n = 5

p = 0.4

P(X)

P(X = 4) = 5! (0.4)4 (1-0.4)5-4

4!(5-4)!

P(X = 4) = 5*0.4*0.4*0.4*0.4*0.6= 0.077

P(X<=3)= P(X=0) + P(X = 1) + P(X=2)+P(X=3)

P(X=0) = 5! (0.4)0 (1-0.4)5-0 0.07776

0!(5-0)!

P(X = 1) = 5! (0.4)1 (1-0.4)5-1 0.2592

1!(5-1)!

P(X=2) = 5! (0.4)2 (1-0.4)5-2 0.3456

2!(5-2)!

P(X=3) = 5! (0.4)3 (1-0.4)5-3 0.2304

3!(5-3)!

P(X<=3) = 0.91296

P(X<2) = P(X=0) + P(X=1)

P(X<2) = 0.33696

P(X>1) = 0.07776

5.15 Mean = np = 20*0.05 = 1

a Standard ...