The class marks of the distribution are 37, 42, 47, 52, 57. Determine the class size and the class limits of one last class mark.
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Answer:
class mark=5.
class limits=54.5-59.5
Step-by-step explanation:
Given: class marks= 37,42,47,52 and 57
class size= difference between two consecutive class marks=42-37=5.
let lower limit of the last class interval='a'.
then, upper limit = a+5.
class mark = average of upper and lower limits of the class interval.
57=(a+a+5)/2,
2a+5=57×2=114,
2a=114-5=109,
a=109/2=54.5.
therefore lower limit = a = 54.5,
and upper limit = a+6 = 54.5+5 = 59.5
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