Question

the co ordinates of a point on the x axis which is equidistance from (2,-5) and (2,-3) are​

Answer 1

Answer:

( - 2, 0 )

Step-by-step explanation:

●___________●___________●

A (2,-5) O x,0 B (2,-3)

x1,y1 x2,y2

Section formula,

mx2 + nx1 my2 + ny1

x, 0 = ________ , ________

m + n m + n

my2 + ny1

0 = ________

m + n

0 = -3m + -5n

- 3m = 5n

m 5

__ = __

n -3

m : n = 5 : - 3

mx2 + nx1

x = ________

m + n

5 ( 2 ) + - 3 ( 2 )

x = ____________

-2

10 - 6

= _____

-2

= 4 / - 2

x = - 2

( x, 0 ) = ( - 2, 0 )

Answer 2

Answer:

Step-by-step explanation:

d = $\sqrt{(x_{2} -x_{1} )^2 +(y_{2} -y_{1} )^2 }$

$\sqrt{(x-2)^2 + (0 +5)^2 }$ = $\sqrt{(x-2)^2 + (0+3)^2 }$ ⇒ 25 = 9 (false)

There is no such a point on the x-axis which is equidistant from (2, - 5) and (2, - 3).