The co-ordinates of the mid point of a line segment are (2, 3). If the co-ordinates of one of the end points of the segment are (5, 6), find the coordinates of the other end point.
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Coordinate of the midpoint = (2,3).
Coordinate of one point =(5,6).
Let the coordinate of the other point be (x,y) .
So, according to the midpoint theorem of coordinate geometry we have ,
→ x+5/2 = 2
or, x+5=4
or, x= -1.
Again → y+6/2=3
or, y +6 = 6
or, y = 0.
Therefore the coordinate of the required point is (-1,6) .
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Coordinate of one point =(5,6).
Let the coordinate of the other point be (x,y) .
So, according to the midpoint theorem of coordinate geometry we have ,
→ x+5/2 = 2
or, x+5=4
or, x= -1.
Again → y+6/2=3
or, y +6 = 6
or, y = 0.
Therefore the coordinate of the required point is (-1,6) .
.
.
.
.
HOPE IT HELPS YOU....
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Please Mark As Brainliest
sajid2580:
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Answered by
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Solution :
Let P( x , y ) = ( 2 , 3 ) is the midpoint of
the line segment AB.
Let A( x1 , y1 )
B( x2 , y2 ) = ( 5 , 6 )
***************************************
We know If the mid point of line
joining of the points A(x1 , y1 ) and
B( x2, y2 ) is P( x , y ) then
x = ( x1 + x2 )/2 ,
y = ( y1 + y2 )/2
*****************************************
Here ,
i ) ( x1 + 5 )/2 = 2
=> x1 + 5 = 4
=> x1 = 4 - 5
=> x1 = -1
ii ) ( y1 + 6 )/2 = 3
=> y1 + 6 = 6
=> y1 = 6 - 6
=> y1 = 0
Therefore
Required point A ( x1 , y1 ) = ( -1 , 0 )
••••
Let P( x , y ) = ( 2 , 3 ) is the midpoint of
the line segment AB.
Let A( x1 , y1 )
B( x2 , y2 ) = ( 5 , 6 )
***************************************
We know If the mid point of line
joining of the points A(x1 , y1 ) and
B( x2, y2 ) is P( x , y ) then
x = ( x1 + x2 )/2 ,
y = ( y1 + y2 )/2
*****************************************
Here ,
i ) ( x1 + 5 )/2 = 2
=> x1 + 5 = 4
=> x1 = 4 - 5
=> x1 = -1
ii ) ( y1 + 6 )/2 = 3
=> y1 + 6 = 6
=> y1 = 6 - 6
=> y1 = 0
Therefore
Required point A ( x1 , y1 ) = ( -1 , 0 )
••••
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