The coach of a cricket team buys 3 bata and 6 balls for Rs. 3900. Later she buys another bat and 3 more balls of the same kind for Rs 1300. Find the cost of one bat and one ball by elimination method?
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Step-by-step explanation:
let the cost of bat be x
and the cost of ball be y.
acc. to the Question:
3x+6y= 3900----------------(1)
x +3y = 1300-----------------(2). {×2]
=> 2x+ 6y = 2600
now by elimination method we get ,
3x+6y= 3900
sub 2x + 6y = 2600
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___________________
x =1300
from (2) we get,
1300 +3y= 1300
3y= 1300-1300
y= 0
therefore , the value of x & y is 1300 and 0 respectively.
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