Question

The coach of a cricket team buys 7 bats and 6 balls for Rs.3800. Later, she buys 3 bats and 5 balls for Rs.1750. Find the cost of each bat and each ball.​

Answer 1

Let the cost of a bat be x and the cost of a ball be y.

According to the question,

7x + 6y = 3800 ………………. (i)

3x + 5y = 1750 ………………. (ii)

From (i), we get;

y = (3800 – 7x)/6 …………………… (iii)

Substituting (iii) in (ii). we get,

3x + 5[(3800 – 7x)/6] = 1750

⇒3x + (9500/3) – (35x/6) = 1750

3x – (35x/6) = 1750 – (9500/3)

(18x – 35x)/6 = (5250 – 9500)/3

⇒-17x/6 = -4250/3

⇒-17x = -8500

x = 500

Putting the value of x in (iii), we get;

y = (3800 – 7 × 500)/6 = 300/6 = 50

Hence, the cost of a bat is Rs 500 and cost of a ball is Rs 50.

Answer 2

Step-by-step explanation:

• Let the cost of one Bat be x
• and the cost of one ball be y
• Then According to Question
• 7x+6y=3800 ---(i)
• 3x+5y=1750 ---(ii)
• multiplying (i) by 3 and (ii) by 7 we get
• 21x+18y=11400 (iii)
• 21x+35y=12250 (iv)
• subtracting (iv) from (iii) we get
• −17y=−850
• ⇒y=50
• putting y=50 in (i)
• 7x+6y=3800
• ⇒7x+6×50=3800
• ⇒7x=3800−300
• ⇒x=500
• Therefore the cost of each bat is Rs 500
• and the cost of each ball is Rs 50