Evaluate integral 1/x^3+x
Answers
Answered by
1
Answer:
Integral [x^(-3) + x] dx
=> x^(-2)/ ( - 2) + x^2/2
=> - x^(-2) /2 + x^2 /2
=> - 1/2x^2 + x^2/2
Answered by
2
Answer:
x²/2 - 2/x² +k
Step-by-step explanation:
∫( 1/x^3+x)dx = ∫( 1/x³+x)dx = -2/x² + x²/2 +k = x²/2 - 2/x² +k
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