Math, asked by shaktimaanss8929, 10 months ago

The coefficient of x2y in the expansion of (4x+5y)3 is equal to

Answers

Answered by harendrachoubay
0

The coefficient of x^2y in the expansion of (4x+5y)^3 is equal to 240.

Step-by-step explanation:

We have,

(4x+5y)^3

To find, the coefficient of x^2y in the expansion of (4x+5y)^3 = ?

Using the algebraic identity,

(a+b)^3=a^{3}+3a^{2}b+3ab^{2}+b^{3}

(4x+5y)^3

Here, a = 4x and b = 5y

(4x+5y)^3=(4x)^{3}+3(4x)^{2}(5y)+3(4x)(5y)^{2}+(5y)^{3}

=64x^{3}+15y.16x^{2}+12x.25y^{2}+125y^{3}

=64x^{3}+240x^{2}y+300xy^{2}+125y^{3}

=(64)x^{3}+(240)x^{2}y+(300)xy^{2}+(125)y^{3}

Clearly, the coefficient of x^2y in the expansion of (4x+5y)^3 = 240

Thus, the coefficient of x^2y in the expansion of (4x+5y)^3 is equal to 240.

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