Question

The collector has current of the NPN transistor is equal to 10 mA. If 90% of the electron from the emitter reaches collector then ......,choose the correct option from the given options.
(A) Ie ≈ 9 mA, Ib ≈ 1mA
(B) Ie ≈ 11 mA, Ib ≈ 9 MA
(C) Ie ≈ 11 mA, Ib ≈ 1m
(D) Ie ≈ 10 mA, Ib ≈ 1m

Answer 1

Answer:

c) Ie ≈ 11 mA, Ib ≈ 1m

Explanation:

Collector current = Ic = 10mA (Given)

Percentage of the electron reaching the collector = 90% (Given)

Thus,

Ic = 90% of Ie

Ic = 90/100 × Ie

Ie = Ic × 100/90

Ie = 10 × 100/90

Ie = 1000/90

Ie = 11.11

Base current = Ib = Ie-Ic

= 11.11 - 10

= 1.1

Therefore, If 90% of the electron from the emitter reaches collector then there will be Ie ≈ 11 mA, Ib ≈ 1m