The combined equation of three sides of a triangle is
(x2 - y2) (2x + 3y – 6) = 0 . If (-2, a) is the
interior point of the triangle then the integral value of a
is
Answers
Answered by
0
Step-by-step explanation:
The combined equation of three sides of a triangle is (x
2
−y
2
)(2x+3y−6)=0. If (−2,a) is an interior point and (b,1) is an exterior point of the triangle, then
THIS QUESTION HAS MULTIPLE CORRECT OPTIONS
Share
Study later
ANSWER
(x
2
−y
2
)(2x+3y−6)=0
(x−y)(x+y)(2x+3y−6)=0
Therefore the lines are
y=x
y=−x
2x+3y−6=0
Since (−2,a) is an interior point
−4+3a−6<0
3a<10
a<
3
10
...(i)
and x+y>0
−2+a>0
a>2 ...(ii)
From i and ii we get 2<a<
3
10
For b consider equations y=x andy=−x
b+1>0
b>−1
and b−1<0
b<1
Therefore −1<b<1
Similar questions