the combining ratio of hydrogen and oxygen in water and hydrogen peroxide are 1:8 and 1:16 which is illustrated in this example
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Answer:
To Determine: To identify the example of the law of multiple proportions.Answer: The option “The mass ratio of oxygen to hydrogen is . The mass ratio of oxygen to hydrogen in hydrogen peroxide is .” is an example of the law of multiple proportions; therefore, the option (c) is correct.Explanation:(a)The law of multiple proportions is for two different compounds of the same elements. Therefore the answer “Two different samples of the water are found to have the same ratio of hydrogen to oxygen.” is not an example of the law of multiple proportions.(b)The law of multiple proportions is for the mass ratioof the same element in the different compound. Therefore the answer “When hydrogen and oxygen react, the mass of the water formed is exactly equal to the mass of hydrogen and oxygen that reacted.” is not an example of the law of multiple proportions.(c)According to the law of multiple proportions, if two different compounds are made up of same elements then the masses of the first element that combine with of the second element can be expressed as a ratio of the whole numberThe mass of oxygen per gram of hydrogen in water is .The mass of oxygen per gram of hydrogen in hydrogen peroxide is .The mass ratio of masses of oxygen per gram of hydrogen in two different compounds is given as: …… (1)Here,is the mass of oxygen per gram of hydrogen present in the first compound.is the mass of oxygen per gram of hydrogen present in the second compound.Substitute for and for in the equation (1).The mass ratio of oxygen per gram of hydrogen in water to hydrogen peroxide is .Therefore the option “The mass ratio of oxygen to hydrogen is . The mass ratio of oxygen to hydrogen in hydrogen peroxide is .” is an example of the law of multiple proportions.
Answer:
Hydrogen and oxygen combine in water in the ratio of 2:1 not 1:8