Question

The combustion of 8g of methane is carried out with 30g of oxygen, for completion of the reaction *
1 point
2g of oxygen is required
2g of methane is required
3g of oxygen is required
3g of methane is required
​

Answer 1

Explanation:

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Answer 2

well let's. see,

methane's atomic mass is 12 and formula is CH4 then,

C=12, H=1×4=4

Total 12+4=16

oxygen's atomic mass = 16 ; doubling - 16×2=32

here it is 30 gm , doubling it and ratio of them will be-

16:32

4:8

2:4

1:2

so , from this,

I think 2g of oxygen is required ...

Hope so you understand , I have my science exam also , so just trying to solve this type questions...