the common difference of an AP is -2 find its sum if first term is 100 and the last term is -10
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Step-by-step explanation:
d=-2
a=100
an=-10
sn=?
n=?
an=a+(n-1)d
-10=100+(n-1)-2
-10-100=(n-1)-2
-110=(n-1)-2
-110/-2=n-1
55=n-1
56=n
sn=n/2(a+an)
=56/2(100-10)
=28(90)
sn=2520
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