Question

The common factor of 6a³b⁴c², 21a²b and 15a³ is​

Answer 1

Answer:

the common factor is 3a²

Answer 2

Given:

6a³b⁴c², 21a²b and 15a³

To find:

The common factor

Solution:

The required common factor is 3$a^{2}$.

We have to represent the given terms as the factors' product to determine the term common between all of them.

The terms given are as follows-

6a³b⁴c², 21a²b and 15a³

Now we will rewrite each one as the factors' product.

6a³b⁴c²=2×3×$a^{3}$×$b^{4}$×$c^{2}$

21a²b= 3×7×$a^{2}$×b

15a³=3×5×$a^{3}$

Now, we see that 3 and $a^{2}$ are common in all the terms.

So, the required factor is 3$a^{2}$.

Therefore, the required common factor is 3$a^{2}$.