Question

The complex numbers $sinx+icosx$ and $cosx-isin2x$ are conjugate to each other when-

(a)$x=0$

(b)$x=\left(n+\frac{1}{2}\right)\pi$

(c)$x=n\pi$

(d) no value of x​

Answer 1

Answer:

Step-by-step explanation:

Complex numbers:-Here,we are provided with a complex number z and its conjugate z bar.

There is a property which states that if we multiply complex number with its conjugate,we get the square of its modulus.

On applying that,we get:-2sin^2(x)=cosx

Now we substitute each of the options in the expression above.

We don't have similar values for any x.

So we get no value of x.

Hence, answer is option D.

Answer 2

Answer:

hope it is helpful to you.