Question

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The compound containing sp, sp2 and sp3 hybridised carbon atoms in 1:2:3 ratio is
a) 2-Methyl-2, 3-pentadiene
b) 1,2-Hexadien 4-yne
c)1,5 -Hexadien–3-yne
d) all the above.​

Answer 1

Explanation:

The ANSWER is (D) All THE ABOVE...

I HOPE IT WILL BE HELP YOU...

Answer 2

(a) 2-Methyl-2,3-pentadiene is the compound containing $sp, sp^{2}, sp^{3}$   hybridized carbon atoms in 1:2:3 ratio.

2-Methyl-2,3-pentadiene:

$H_3C-C(CH_3)=C=CH-CH_3$

    1       2 3           4      5        6

In this structure 1,3,6 number carbons are $sp^{3}$ hybridized, 2,5 numbers carbons are $sp^{2}$ hybridized and number 4 carbon is $sp$ hybridized.

So, the ratio of $sp, sp^{2}, sp^{3}$ hybridized carbon in (a) 2-Methyl-2,3-pentadiene is 1:2:3 respectively. So, it is the correct answer.

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