Question

the compound interest on 15625rs. for 3/2 years at 8%per annum compounded half yearly​

Answer 1

Step-by-step explanation:

Here the principle=15625rs.

Rate of interest(R)= 8/2 =4% ( as for half yearly)

Time (n) = 3/2 ×2 =3 half years

AMOUNT (A) =P(1+R/100)^n

A=₹15625×(1+4/100)^3

=₹17576

therefoe COMPOUNT INTEREST (C.I.)= A-P=₹17576-₹15625= ₹1951

Answer 2

$\sf \bold\green{\underline{✧ Given :-}}$

• P(principal) = ₹15625
• T(time) = 3/2 years
• R(rate) = 8%

$\sf\green{\underline{✧To \: find:-}}$

• The compound interest (compounded half yearly)

$\sf\green{\underline{✧ Solution :- }}$

• As we know that here the P(principal) is compounded half yearly.
• Hence, the rate will be 4% and the T(time) will be n = 3

So,

Formula :-

$\sf {\underline{ \boxed{\pink \bigstar \sf A(amount)= P(principal) \times ( { \frac{R(\%)}{100}) }^{n} }}}$

Where,

• R(rate) = 4%
• T(time) = 3 i.e., n

$\sf \therefore \: A \: = 15625 \times (1 + { \frac{ \cancel4}{ \cancel{100}} )}^{3} \\ \sf \implies A= \cancel { 15625 }\times \frac{26}{ \cancel{25}} \times \frac{26}{ \cancel{25}} \times \frac{26}{ \cancel{25}} \\ \sf \implies \: A =₹ 17576$

$\sf \therefore \: Compound \: interest \: = Amount \: - Principal \\ \bf = ₹(17576 - 15625 )\\ \bf = ₹1951$

$\sf { \green\bigstar{ \underline{ \boxed{\sf Compound \: interest \: ={\blue{₹ 1951\:\:☞\:\:ans.}}}}}}$