The compound interest on a certain sum of money for 2 year at 5% is 328, then the sum is?
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Let,
Principal = P
Interest rate = r% p.a. compounded annually
Interest = I
Amount = A= P+I
Compounding No. = n i.e. no. of times in a year interest is calculated
Time = t = expressed in no. of years
As per C.I. formula
A = P.( 1+r%/n)^(nt)
I = A- P
= P.( 1+r%/n)^(nt) -P
= P[ (1+r%/n)^(nt) -1] = 328
or, P [ (1+5/100/1)^1*2 -1] = 328
or, P [ (1.05)^2 -1] =328
or, P [ (1.05)^2 -1^2] = 328
or, P [ (1.05+1)*(1.05-1)]=328 (by applying a^2-b^2= (a+b)(a-b) formula)
or, P (2.05*.05) = 328
or, P (0.1025) = 328
or P= 328/.1025 = Rs. 3200
Hence, principal was Rs. 3200
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