The compound interest on a certain sum of money is $630 for 2 years at a rate of 10% per annum What is the corresponding simple interest?
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Answer:
It is given that
Period = 2 years
Rate = 10% p.a.
We know that
Sum = (SI×100)/(r×n)
Substituting the values
= (1600×100)/(10×2)
= 8000
Amount after 3 years =P(1+r/100) n
Substituting the values =8000(1+10/100) 3
By further calculation
=8000×11/10×11/10×11/10=10648
So the compound interest = A -P
Substituting the values
= 10648−8000
= 2648
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