Question

the compound interest on rs 5000 at 10% annum for two years is​

Answer 1

Answer:

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Step-by-step explanation:

The compound interest is 21%.

The compound interest is 21%.Explanation:

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yr

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.= 1050.

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.= 1050.So 5000 * x = 1050

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.= 1050.So 5000 * x = 1050x = 1050/5000 = 0.21

The compound interest is 21%.Explanation:C.I = P [(1 + r/100)n - 1]P = 5000r = 10%n = 2yrSo, C.I = 5000 [(1 + 10/100)^2 - 1= 5000[(1.21 - 1)]= 5000 * 0.21.= 1050.So 5000 * x = 1050x = 1050/5000 = 0.21x = 0.21 * 100 = 21%.

Answer 2

Answer:

The compound interest is 21%.

Explanation:

C.I = P [(1 + r/100)n - 1]

P = 5000

r = 10%

n = 2yr

So, C.I = 5000 [(1 + 10/100)^2 - 1

= 5000[(1.21 - 1)]

= 5000 * 0.21.

= 1050.

So 5000 * x = 1050

x = 1050/5000 = 0.21

x = 0.21 * 100 = 21%.