The compound interest on rupees 25000 for 3 years at 10% per annu, compounded annually.
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8275
Step-by-step explanation:
p= 25000
t= 3 years
rate = 10
so interest for 1st year = 10% of 25000= 2500
so after 1st year amount becomes 25000+2500= 27500
interest for 2nd year = 10% of 27500 = 2750
so after 2nd year the amount becomes 27500+2750 = 30250
interest for 3rd year = 10% of 30250 = 3025
so compound interest for 3 years = 2500+2750+3025 = 8275
it can also be solved using the equation A= P(1+R/100)ⁿ
A= 25000(1+10/100)³
25000*11/10*11/10*11/10
=33275
So compound interest = 33275 -25000 = 8275
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