Question

The compound interest on rupees 4000at 10% per annum for 2 years 3 months compounded annually is​

Answer 1

Answer:

please see the above attachment

Answer 2

Required answer:-

Principal (P)=Rs.4000

Rate of Interest (r)=10%

Time =2 years and 3 months

Here first we take n=2 years.

⇒ Amount for first 2 years (A) =

$= p(1 + \frac{r}{100} ) {}^{2}$

$= 400 + (1 + \frac{10}{100} ) {}^{2}$

$= 4000( \frac{11}{10} ) {}^{2}$

$= 4000 \times \frac{121}{100}$

⇒Rs.4840.

⇒ The amount after two years =Rs.4840

⇒ Now, Principal =Rs.4840

Simple interest for last 3 months i.e.

$\frac{1}{4} years$

⇒

$\frac{prt}{100}$

$\frac{4840 \times 10 \times 1}{100 \times 4}$

Rs.121.

⇒ Amount after 2 years and 3 months =Rs 4840+Rs.121=Rs.4961

⇒ C.I.=A−P

=Rs.4961−Rs.4000

=Rs.961

∴ The compound interest is Rs.961.

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